Mathematics
8 Online
OpenStudy (anonymous):
help!
use the quadratic formula to solve
x²+3=-4x
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OpenStudy (anonymous):
x^2+4x+3 = 0
(x+1) (x+ 3) = 0
then x = -1 or x = -3
OpenStudy (anonymous):
no no use quadratic formula to solve @gerryliyana
OpenStudy (anonymous):
do you know what the quadratic formula is? or are you asking for that.
OpenStudy (anonymous):
i know what it is but i still dont know how 2 get the answer...
OpenStudy (anonymous):
set up equation so that you have:
ax^2+bx+c=0
and use a, b and c correctly in your formula
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OpenStudy (anonymous):
x²+4x+3=0?
OpenStudy (anonymous):
so a=?,b=?, and c=?
OpenStudy (anonymous):
yess ur all right
OpenStudy (anonymous):
smart boy!!
OpenStudy (anonymous):
a=o b=4 c=3
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OpenStudy (anonymous):
nooo
OpenStudy (anonymous):
a = 1, b=4, c=3
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
sorry i wasnt thinking
OpenStudy (anonymous):
so now what?
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OpenStudy (anonymous):
use
\[x = \frac{ -b \pm \sqrt{(b^{2} - 4ac)} }{ 2a }\]
OpenStudy (anonymous):
substitute all parameter, including a, b, and c
OpenStudy (anonymous):
to solve x²+4x + 3 =0 you should find the value of x, one way to do this by using formula above ...,
OpenStudy (anonymous):
\[x = \frac{ -b \pm \sqrt{b^{2}-4ac} }{ 2a }\]
\[x = \frac{ -4 \pm \sqrt{4^{2}-(4)(1)(3)} }{ 2(1) }\]
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
Thanks both of you!