Question

Find the product of (3x − 7y)^2

Answer 1

Use the formula : \[(a-b)^{2} = a ^{2} - 2ab + b ^{2} \]
by substituting a = 3x
b = 7y.
Can you do that? :-]

Answer 2

9x2 − 49y2?

Answer 3

@Jas9420

Answer 4

Hi!

(3x+7y) (3x-7y)

Difference of squares = a^2 - b^2 = (a+b) (a-b)

(3x)^2 - (7y)^2

9x^2 - 49y^2


(3x-7y)^2
Perfect squares
(a-b)^2= a^2 -2ab + b^2
(3x)^2 -2(3x)(7y) + (7y)^2
9x^2 - 42 xy + 49y^2


(x+5)^2

Perfect squares property
(a+b)^2 = a^2 + 2ab + b^2

(x)^2 + 2(x)(5) + (5)^2
x^2 + 10 x + 25

Hope this helps!

Answer 5

No @allie_bear22
You get \[(3x)^{2} - 2\times3x \times 7y + (7y)^{2}\]

Answer 6

@blackprincesssen so was i right? 9x2 + 49y2

Answer 7

Can you simplify it now?

Answer 8

@Jas9420 i know i did the rest my self and wanted to know if my answer was right

Answer 9

yes

Answer 10

Ah, yes. But you did do the whole thing, right?

Answer 11

i hope i help if i did

Answer 12

yea u did

Answer 13

tnx u guys