Which equation has this graph? http://curriculum.kcdistancelearning.com/courses/ALG1x-HS-CA10/b/Exams/8Quiz1/8Quiz1_q1.bmp
Explain so i can understand. please(:
y = x2 - 6x + 5 y = -x2 - 6x + 5 y = -x2 - 6x - 5 y = x2 + 6x - 5
What are the two roots here? How do you write a general equation for a quadratic?
You have to be quick. I have to go soon.
2+bx+c?
So basically you have to look for what equals (3,4)
You see those options on top? i think we have to chose one. idk o_o
NO WAIT I MEAN (3,-4)
lol brain fart
Roots here are x=1 and x=5. It is where the function has the value 0. So your quadratic would be (x-1)(x-5)=0 ..
(1,-5)? O:
LOL JESS.
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KK ITS 1,5
OMG I SUCK AT THIS.
Wait yre
Yeah you really do. Yes jess?
This is sad.
It has to be the first one..
Yes, it is the first one.
jk umar.
Im crying guys. this is too sad.
thanks tho. i didnt understand a thing.
Yre!! It's the first one!!!!!!
Crying is girlish... :P And you understand it now? It is the first one, jess. :P
x-intercept The value of x at the point where a line or curve crosses the x-axis. : (1,0),(5,0) y-intercept The value of y at the point where a curve crosses the y-axis. : (0,5)
its okay for guys to cry over math... and i still dont understand lol. Jess what is that? D:
That's your answer lol
erm. thank you guys.
When you got two zeros of a quadratic (x-x1)(x-x2)=y gives you the quadratic. Here x1=1, x2=5, find the quadratic..
And as this is an objective question, you could also put x=1 and x=5 in each of the options and see where y is zero. You can eliminate the options that do not satisfy your condition.
okay i understand now(:
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