What are the approximate solutions of 2x2 − 7x = 3 rounded to the nearest hundredth? No real solutions x ≈ −0.77 and x ≈ 7.77 x ≈ −0.39 and x ≈ 3.89 x ≈ −3.89 and x ≈ 0.39
Im confused by this problem. 2x2 would make people think you're multiplying 2 by 2. What does the equation really look like?
2x^2 - 7x = 3
Oh ok
factor first: (2x-1)(x-3)
so either 2x-1=0 or x-3 = 0
so x= 1/2 or x = 3
that is not in the choices though
yeah... somethings wrong...
2x^2 - 7x = 3 2x^2 - 7x - 3 = 0 (2x-1)(x-3) ===> this line's wrong
so how do i solve it?
y = ax^2 + bx + c y = 0 at x points of:
\[ \frac{ -b +/-\sqrt{(b ^{2}-4ac} }{ 2a }\]
i'm confused
so: from your equation a = 2 b = -7 c = -3 sub those numbers into the equation I gave you and you'll get answers for x
\[x = \frac{ 7 - \sqrt{73} }{ 4}\]
\[or x = \frac{ 7 + \sqrt{73} }{ 4}\]
so x = 3.886 and x = -0.386
ok thanks for the help
all good, sorry for the stuff up earlier
thats fine
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