Can someone help ?
do you know what rationalizing the denominator means?
nope @Tomas.A
Well as you should know square over some number means that it will be irrational, so you should remove square from denominator. How to do that? Well I hope you know that \[\sqrt{2}\times\sqrt{2}=\sqrt{2\times2}=\sqrt{2^2}=2\] use same principle, you can multiply denominator and numerator by same number
. . . and then ? @Tomas.A
when you do that it will be rationalized
i have no idea what youre talking about im sorry im really confused @Tomas.A
multiply denominator and numerator by \(\sqrt{30}\)..
whats the numerator and denominator ? @Tomas.A
\[\frac{this\ is \ numerator}{this\ is\ denominator}\]
i know . . but in the problem @Tomas.A
\(4\sqrt{6}\) is numerator in your problem and \(\sqrt{30}\) is denominator
53.6 ? ? ? and 30 ??? @Tomas.A
i dont know whats that
ugh. i have no idea how to do this .
\[\frac{4\sqrt{6}\times\sqrt{30}}{\sqrt{30}\times\sqrt{30}}=\frac{4\sqrt{6}\times\sqrt{5\times6}}{30}=\frac{4\times6\sqrt5}{30}=\frac{24\sqrt5}{30}=\frac{4\sqrt5}{5}\]
That would be the answer ?
yeah..
can i say something ?
yes
I love you . thank you. life saver. @Tomas.A
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