Question

How do I solve n^2+16n+64=36

Answer 1

well subtract 36 from both sides of the equation

\[n^2 + 16n + 48 = 0\]

find the factors of 48 that add to 16... 12 and 4

then you show the equation as the product of 2 binomials.

(n + factor 1)(n + factor 2) = 0

then its simply a case of solving

n + factor 1 = 0 and n + factor 2 = 0


the reason is, if either binomial is equal to zero, then the equation will equal zero.

Answer 2

Thank you