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Can somone please help me with this problem
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\[h'(1)=f'(g(1))\times g'(1)\] all those numbers are know, plug them in and see what you get
There is no g number
\[g(1)=3, f'(3)=-5, g'(1)=-3\] you get \[f'(g(1))\times g'(1)=f'(3)\times (-3)=-5\times -3\]
so then h'(1) =15
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yes
ok but one question how do you know that g(1)
it says
i closed it out, but it said on the paper that \(g(1)=3\)
ok thanks
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