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What is the probability of selecting a red marble, replacing it, and then selecting a blue marble? Show your work. b. What is the probability of selecting a red marble, setting it aside, and then selecting a blue marble? Show your work. c. Are the answers to parts (a) and (b) the same? Why or why not? There are 4 red 5 green and 7 blue
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multiply the probability you pick a red marble first, by the probability you get a blue marble second difference between the first and second is that in the first the probability you get a blue marble second is \(\frac{7}{16}\) whereas in the second problem it is \(\frac{7}{15}\) because in the second one the red marble has been removed, leaving only \(15\)
thank you so much c:
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