Question

11. A car is pulled with a force of 10,000 N. The car's mass is 1267 kg. But, the car covers 394.6 m in 15 seconds. (a) What is expected acceleration of the car from the 10,000 N force? (b) What is the actual acceleration of the car from the observed data of x and t? (c) What is the difference in accelerations? (d) What force caused this difference in acceleration? (e) What is the magnitude and direction of the force that caused the difference in acceleration? *im in 7th grade please explain in terms i know! thanks.

Answer 1

There are four equations you can choose from in order to solve this problem, though not all are needed. Here are all four of them: \[F=ma\]\[V _{f}=V _{0}+at\]\[X _{f}-X _{0}=V _{0}t+\frac{ 1 }{ 2 }at ^{2}\]\[V _{f}^{2}=V _{0^{2}}+2a(X _{f}-X _{0})\]\[V _{f}=final velocity, V _{0}= initial velocity, X _{f}= final distance, X _{0}= initial distance\]You can pick from these equations to solve the problem. Obviously you will have to do some rearranging. Ut is really helpful to have these equations memorized because they are the founding fathers of kinematics, though I do understand you are a 7th grader.

Answer 2

If you are still stuck, feel free to respond with more questions.