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Write g(x) = 3cos(5x) +3sqroot3sin(5x) in terms of sine only. Please help.
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\[b\cos(x)+a\sin(x)=\sqrt{a^2+b^2}\sin(x+\theta)\] for the appropriate \(\theta\)
find \(\theta\) via \[\sin(\theta)=\frac{a}{\sqrt{a^2+c^2}}\] and \[\cos(\theta)=\frac{b}{\sqrt{a^2+b^2}}\]
I get the answer 6sin(5x+pi/3) but, its wrong
lets see
yeah i screwed up that is why
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it is \[\cos(\theta)=\frac{a}{\sqrt{a^2+b^2}}\] and \[\sin(\theta)=\frac{b}{\sqrt{a^2+b^2}}\]
this gives \(\theta=\frac{\pi}{6}\) i had it backwards
thank you (:
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