Question

.

Answer 1

Are you SURE you mean \(h(x) = 3x + \dfrac{2}{4x} - 9\)? That IS what you wrote.

Answer 2

\[h(x)=\frac{ 3x+2 }{ 4x-9 }\] sorry about that

Answer 3

Parentheses work wonders.

#1 What are the Domain and Range of h(x)?

Answer 4

yes I need to find the Domain and range \[(h ^{-1})=\] and \[h ^{-1} (x)=\]

Answer 5

No, you FIRST need the Domain and Range of h(x). What are they? We are NOT ready to find the inverse until we know this.

Answer 6

okay so this must sound dumb but how would I go about finding the domain and range I am a bit out of practice on that part..

Answer 7

Generally,

Domain ==> What values go in.
Range ==> What values come out.

This is a rational function.

You are expected know that anytime the Denominator is zero, the value of x that causes this problem is NOT in the Domain.

You are expected know that a horizontal asymptote may not be included in the Range.

Answer 8

so would the range be all real numbers except 9/4 and range be all real numbers except 3?

Answer 9

Not Quite

Domain: \(x \ne 9/4\)
Range: \(y \ne 3/4\)