I need a little help in making the first assumptions at the moment 0+. How do I deal with the charged Cap knowing the things written in pencil on the right side?
Picture incoming :D

Question

I need a little help in making the first assumptions at the moment 0+.  How do I deal with the charged Cap knowing the things written in pencil on the right side?
Picture incoming :D

anonymous · Answer

This is my first step. On the right track?

espex · Answer

If the switch has been closed for a very long time then the capacitor would look like an open circuit at 0-, and since the voltage cannot change instantaneously, V0- = V0+

kenljw · Answer

The voltage across a  capacitor is the Integral of the current through it, therefore the voltage at 0- is the Integral from -infinity to 0-.  If at t = 0 the capacitor is shunted by and non zero resistance or a capacitor with internal resistance then the voltage 0- = 0+ ie the voltage can't change instantaneously across a capacitor.  If your talking about to ideal capacitors when one is shunted by another then the voltage at 0- doesn't equal the voltage at 0+, you must us the equation CV = Q to solve due to impulse of current at t = 0.