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I am really confused please help.
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I will write down the question
When???
\[\int\limits_{} (xcos(x^3))^2 dx \]
\[\int\limits_{1}^{0} x^2\sqrt{4-3x}dx\]
compute intergrals
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\[1/6(x^{3}+\sin(x ^{3}cosx ^{3})\]
its supposed to say sin x cubed times cosine x cubed
looks to be by parts
mmm im even more confused!
\[~~~~~~~~~~~~~v\\+~u~\int v\\-~u'~\int\int v\\+~u'''~\int\int \int v\] if u is a poly, itsll eventually derive to zero; then you add up the products of each row
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this is the rule?
thats a by parts table setup yes but there may be a simpler method for these
I see. How do i solve my problems? :/
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