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find the solution set for this equation.. b^2+12b=0
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could you define solution set for me? i know i can solve this, but im not quite sure what you are looking for when you say solution set
a solution set is the set of values that satisfy a given set of equations or inequalities.
b(b-12)=0, b=0,12
wrong!!
make taht negate 12 lol
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wait whats the question again?
im pretty sure its 0, -12, try these values in the equation they both = 0.
ok, so basically the answers to the problem. and i got the same answers as @Lost_in_Translation so i belive they should be correct
The solutions to this answer are:\[x=-12\] and \[x=0\]
ok
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