Question

Math help

Answer 1

@jim_thompson5910

Answer 2

A+B = C

B = C - A

Answer 3

to find B, you need to subtract C-A

which means you subtract x-y where x is a number in matrix C and y is a corresponding number in matrix A

Answer 4

for example 5-3

Answer 5

you have it backwards

Answer 6

5+3 ?

Answer 7

C comes first, then A

so 3 - 5 = -2

and this is row 1, column 1

Answer 8

Ohhh that way.

Answer 9

yeah

Answer 10

So my answer would be

[-2 3 -1]
-4 8 -5

Answer 11

your signs are off for every term but one

Answer 12

it *should* be this

-2 -3 1
4 -8 5

Answer 13

if you subtract in the wrong order, then the sign will be off

Answer 14

Yeah thats what i have. I didnt put that ?

Answer 15

no you had the opposite signs

Answer 16

Haha man

Answer 17

D+E = 0

E = 0 - D

E = -D

E = -1*D

Answer 18

so you just multiply everything in D by -1 to get the matrix E

Answer 19

Example ?

Answer 20

the 5 in the upper left corner will turn into -1*5 = -5

Answer 21

do the same for every number in matrix D

Answer 22

??

Answer 23

do i put 2 rows at the end or just 1 ?

Answer 24

do you see matrix D

Answer 25

Oh yes so just add or multiply

Answer 26

multiply every number in matrix D by -1

Answer 27

5*-1 ?

Answer 28

My answer ?

Answer 29

got the same

Answer 30

4x - x = 12

Answer 31

0 - (3y+6) = 4y+8

Answer 32

Huh ?

Answer 33

4x - x = 12

x = ??

Answer 34

4

Answer 35

good

Answer 36

so its x=4 and y=-2

Answer 37

yeah

Answer 38

@jim_thompson5910

Answer 39

this will be the last one, i don't wanna do all of them ok?

Answer 40

ok. :(

Answer 41

do i multiply ?

Answer 42

Its 1:51am here i need to finish this.

Answer 43

yeah you multiply everything in matrix A by 6

multiply everything in matrix B by 5

then you subtract

Answer 44

one sec though

Answer 45

I still don't get it but okay.

Answer 46

we have this

\[\large 6\left[\begin{array}{ccc}-3 & 7 & 1 \\9 & 8 & -5 \\ \end{array}\right]
- 5\left[\begin{array}{ccc}-4 & 3 & -9 \\3 & 7 & 6 \\ \end{array}\right]\]

Answer 47

-38

Answer 48

multiply EVERY element in the first matrix by 6

and

multiply EVERY element in the second matrix by 5 this will give you

\[\large \left[\begin{array}{ccc}6(-3) & 6*7 & 6*1 \\6*9 & 6*8 & 6(-5) \\ \end{array}\right] - \left[\begin{array}{ccc}5(-4) & 5*3 & 5(-9) \\5*3 & 5*7 & 5*6 \\ \end{array}\right]\]

which turns into

\[\large \left[\begin{array}{ccc}-18 & 42 & 6 \\54 & 48 & -30 \\ \end{array}\right] - \left[\begin{array}{ccc}-20 & 15 & -45 \\15 & 35 & 30 \\ \end{array}\right]\]

Answer 49

-18--20=-38 ?

Answer 50

-18 - (-20) = -18 + 20 = 2

Answer 51

Ohh okay

Answer 52

I got my answer.

Answer 53

ok great

Answer 54

Is that it? Or can we keep going so i can finish tonight wel this morning since its 2am

Answer 55

well the rest should hopefully be similar

Answer 56

It is.

Answer 57

ok then try to use the ideas shown above to get the rest

Answer 58

It gets harder & harder.

Answer 59

well do what you can first, then come back to the ones you're stuck on

Answer 60

and maybe you'll know how to do them when you come back

Answer 61

Were almost done. I guess thats the good news. You've been a big help lol & thats why i do my work late bc your online.

Answer 62

how much is left

Answer 63

and again i don't want to do it all, you should try a few yourself

Answer 64

I lied its 17 left

Answer 65

I'm not saying you're lazy or anything, it just helps to participate and do the problems (it helps you learn it much better)

Answer 66

that's a lot

Answer 67

It is actually. Am im just tired & want to get this done honestly.

Answer 68

why not break them up over a few days or something

Answer 69

Can't do that. Its a practice due today

Answer 70

oh i see

Answer 71

assessment *

Answer 72

Yeah thats why im up or ill be sleep.

Answer 73

ideally this is something you should do on your own because it wants to assess where you are in the class (without any notes, help, etc)

Answer 74

College prep. I only go to that class once a week

Answer 75

Math is my worst subject. Always has been since 6th grade

Answer 76

really? that's very infrequent...

Answer 77

well practice practice practice, that's how anyone gets better at anything

Answer 78

They start you off with the "easy" stuff they say then overall it gets harder & harder,

Answer 79

Man i just need to finish

Answer 80

If you can't help me threw it all thanks anyways. You've been a big help !

Answer 81

I can help with a few (even though I probably shouldn't), but again, don't want to do them all

Answer 82

Your awesome :)

Answer 83

just make sure you get more practice in, the more you practice, the better you'll get

Answer 84

Oh i will when i go back to my class as of right now . i need the help.

Answer 85

how would you isolate X

Answer 86

subtract ?

Answer 87

subtract what from both sides

Answer 88

so it would be -13 to start off with correct ?

Answer 89

in the upper left corner, yes

Answer 90

after you do all the subtractions, tell me what you get