Question

a triangle has side lenths of 9cm, 40cm, 41cm, show mathematicly that it is a right angled triangle

Answer 1

do u know pythagores theorem
??????????

Answer 2

yes

Answer 3

just apply that

Answer 4

but i dont know how to explain

Answer 5

the hypotenuse it the longest side of the triangle

Answer 6

prove lhs = rhs
H^2=P^2+B^2

Answer 7

where H is hypotenuse P prpendicular B base

Answer 8

i dont understand

Answer 9

what is H here?

Answer 10

41 cm

Answer 11

ok

Answer 12

then H^2=?

Answer 13

whats the triangle thing

Answer 14

its representation of square

Answer 15

oh okay

Answer 16

since there is no small subscript

Answer 17

@UnkleRhaukus how to show squre of a no?

Answer 18

```
\[H^2=P^2+B^2\]
```
\[H^2=P^2+B^2\]

Answer 19

\[41^2=41\times41\\=(40+1)\times(40+1)\\=40(40+1)+1(40+1)\\=\]

Answer 20

ohk u r genius :)

Answer 21

a^2 + b^2 = c^2 (c is the hypotenuse)
9^2 + 40^2 = 41^2
81 + 1600 = 1681
1681 = 1681 (correct)

Answer 22

40(40+1)+1(40+1)
=1600+40+40+1
=1681