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Find the sum of the first 12 terms of the sequence. Show all work for full credit. 1, -4, -9, -14, . . .
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define a rule of expression that defines the sequence
once you know how to determine {a_n} then summing is simple enough
\[S _{n}=\frac{ n }{ 2 } [2a + (n-1)d]\]
for an arithmetic sequence:\[\sum_{n=a}^b(a_1+d(n-1))=\frac{b(a_1+a_b)}{2}\]
my choice of letters wasnt good lol
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n=is the number of terms a=1st term d=common difference Sn=Sum of the n terms
\[\sum_{n=p}^q(a_p+d(n-1))=\frac{q(a_p+a_q)}{2}\] might be better
ugh ... the range is not q, but q-p ... oh well
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