Mathematics
18 Online
OpenStudy (anonymous):
Someone please help me!!
secxcscx=2cscx
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (loser66):
recheck the problem, please, I don't think you post the right one
is it sec (x) * csc (x) = 2 csc (x)?
OpenStudy (loser66):
@yeshapatel97 knock, knock
OpenStudy (anonymous):
yeah it's sec(x)*csc(x)=2 csc(x)
OpenStudy (loser66):
so, the question is solve for x?
OpenStudy (loser66):
or prove?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
it's to solve for x
OpenStudy (anonymous):
lets start from the left and work towards the right...
answer these:
secx = ??
cscx = ??
OpenStudy (loser66):
ah ... sorry, I misunderstood. think it is proving
OpenStudy (loser66):
ok, let dpalnc guides you,
OpenStudy (anonymous):
@dpaInc there aren't any values for cscx or secx
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
1/sinx=cscx 1/cosx=secx
OpenStudy (anonymous):
yeah that makes sense
OpenStudy (anonymous):
okay that makes sense
OpenStudy (anonymous):
hang on...
OpenStudy (anonymous):
no here's an attachment of the problem
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
because this is not an identity, the instruction must be to solve the equation, is that right?
OpenStudy (anonymous):
yeah i know it's not an identity, but yeah you have to solve for x
OpenStudy (anonymous):
i was under the impression that we needed to prove that statement... sorry...
OpenStudy (anonymous):
it's alright...
OpenStudy (anonymous):
ok.. let's see if we solve the equation...
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
bring that right side over to the left side... what u got as a result???
OpenStudy (anonymous):
sec(X)csc(x)-2csc(x)=0
OpenStudy (anonymous):
ok.. now factor cscx from that left side... what u got now???
OpenStudy (anonymous):
cscx(secx-cscx)=0
OpenStudy (anonymous):
what happened to te "2" ??
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
try factoring again...
OpenStudy (anonymous):
cscx(secx-2)
OpenStudy (anonymous):
=0
OpenStudy (anonymous):
ok.. thats better... now using the zero product property:
cscx = 0 OR secx - 2 = 0
ok so far???
OpenStudy (anonymous):
does the first one have a solution???
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
oh oky i know what to do from here
OpenStudy (anonymous):
ok...:)
OpenStudy (anonymous):
no the first one doesnt
OpenStudy (anonymous):
thank you :)
OpenStudy (anonymous):
correct.. that first one does not have a solution...
so your solutions must come from secx - 2 = 0,
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yw....:)