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OpenStudy (anonymous):
the
OpenStudy (mertsj):
Which part?
OpenStudy (anonymous):
do you want to have answer for all of them? I know just one: the coordinate of A and B, If you want to know, I will give you mine, If you don't want, I am ok :)
OpenStudy (anonymous):
which part u can help with
OpenStudy (anonymous):
the first two is Co Ordinate Gemmetry and the other two matrices
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OpenStudy (anonymous):
@Mertsj help him, please. I am hang off
OpenStudy (mertsj):
I repeat my original question. Which part do you want help with?
OpenStudy (anonymous):
if possible all
OpenStudy (anonymous):
or guide me through them
OpenStudy (mertsj):
Do you know how to graph ordered pairs?
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OpenStudy (anonymous):
never heard about it
OpenStudy (mertsj):
Could you graph this point? (3,2)
OpenStudy (anonymous):
i think so
OpenStudy (anonymous):
|dw:1366561301321:dw|
OpenStudy (anonymous):
is it like this
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OpenStudy (mertsj):
Yes. So you need to find points A and B
OpenStudy (anonymous):
is it -2, 3
OpenStudy (anonymous):
sorry
OpenStudy (mertsj):
Could I ask you why you have to do these problems?
OpenStudy (anonymous):
is it -2, 6
3, 4
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OpenStudy (anonymous):
not sure
OpenStudy (mertsj):
The points are (4,6) and (-2,3) They must also be written in the proper form.
OpenStudy (anonymous):
ok i'll try the other parts of the question and u will tell me if the answers are correct in a while
OpenStudy (mertsj):
ok
OpenStudy (anonymous):
not sure about the equation of the line, but is the gradient 7/4
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OpenStudy (anonymous):
is the gradient correct
OpenStudy (anonymous):
gradient is 1/8
OpenStudy (mertsj):
Use the coordinates of the points A and B to find the gradient. The formula is:
\[\frac{y _{2}-y _{1}}{x _{2}-x _{1}}\]
OpenStudy (anonymous):
yes i did
OpenStudy (anonymous):
and that the answer i got -2 - 6 = 8 for x2-x1
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OpenStudy (mertsj):
|dw:1366564219681:dw|
OpenStudy (anonymous):
please don't get weary with me, but -2 and 6 are not on the x axis
OpenStudy (mertsj):
I thought you were trying to find the slope of the line.
OpenStudy (anonymous):
sorry i label it wrong i just went it over and saw my mistake, that is why confirmation is good. Thank you much.
OpenStudy (anonymous):
please help twith the equation
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OpenStudy (mertsj):
Now that you know a point on the line and you know the slope, use point-slope form.
OpenStudy (anonymous):
sorry was out but what is point slope form
OpenStudy (mertsj):
\[y-y _{1}=m(x-x _{1})\]
OpenStudy (anonymous):
am not getting it
OpenStudy (anonymous):
am getting all kind of figures
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OpenStudy (mertsj):
What point did you choose?
OpenStudy (anonymous):
i use x1-x2, y1-y2 all over 2 i got 1, 3/2 and cannot go any further
OpenStudy (mertsj):
Please answer the questions I ask you. I ask a specific question for a reason. We know two points on the line. A and B. Pick one of them and tell me which one you have chosen.
OpenStudy (anonymous):
b
OpenStudy (mertsj):
B is the point (4,6)
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