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Mathematics 21 Online
OpenStudy (anonymous):

factoring polynomials 21^2+31x+4

OpenStudy (anonymous):

What do you want to do with this?

OpenStudy (anonymous):

factor

OpenStudy (anonymous):

First, what is 21^2?

OpenStudy (anonymous):

You can put it into a calculator if you want. It's the same as 21*21

OpenStudy (anonymous):

3x+444

OpenStudy (anonymous):

its 3x+444?

OpenStudy (anonymous):

No, it actually isn't. The idea behind openstudy is that we help you find the answer, not give it to you.

OpenStudy (anonymous):

ok so if its not then 21x21 is 441 then what?

OpenStudy (anonymous):

Okay, since 31 is a prime number, we can't factor it. So, can you evenly divide 441 by 31(with no remainder)?

OpenStudy (anonymous):

no its 14.226

OpenStudy (anonymous):

Right, that .226 means it doesn't divide evenly.

OpenStudy (anonymous):

So, we get 441 + 31x. This is because it is irreducible. Only one term has x, and only 1 term is divisible by the smallest number 31.

OpenStudy (anonymous):

Ahh...made the mistake twice. We get 445 + 31x when you add the 4.

OpenStudy (anonymous):

oh i c:)

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