Question

what is 1/root2 + 1/2 ?

Answer 1

\[1/\sqrt{2}+1/2\]

Answer 2

how to make Lcm of that ?

Answer 3

Try multiplying both the numerator and denominator in \(\dfrac{1}{\sqrt 2}\) by \(\sqrt{2}\)

Answer 4

@k.m.imran
add like this
\[\frac{ 1 }{ a } + \frac{ 1 }{ b } = \frac{ b+a }{ ab }\]

Answer 5

1/sqrt2+2=sqrt2/2+1/2=(sqrt2+1)/2=(1.414+1)/2=2.414/2=1.212 approx.

Answer 6

following @ParthKohli's steps you'd get.
\[
{\sqrt{2}\over2}+{1\over2}=
\]
this is now a simpler base to proceed