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OpenStudy (anonymous):
eliminate the parameter. x = 5 cos t, y = 5 sin t
help please!
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OpenStudy (amistre64):
which parameter?
OpenStudy (gorv):
@coolkat4
cost=x/5
sint=y/5
sint^2+cost^2=1
(x/5)^2+(y/5)^2=1
x^2+y^2=25
OpenStudy (amistre64):
if it means solve for y in terms of x, solve for t in terms of x
OpenStudy (anonymous):
okay i understand that. now what exactly is eliminating the parameter mean? is that the x^2+y^2=25
OpenStudy (amistre64):
generally, it means creating a: y=______ type setup such that y is a function of x
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OpenStudy (anonymous):
so after x^2+y^2=25 where do i go from there?
OpenStudy (gorv):
yes here t is the parameter
this the final answer
parameters are eliminated
OpenStudy (gorv):
got it????
OpenStudy (anonymous):
kind of..Eliminate the parameter. x = t^2 + 1, y = t^2-1....would the answer be in the same form?
OpenStudy (amistre64):
solving t^2 in terms of x, we get t^2 = x-1
sub that into t^2 in the y side and simplify
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OpenStudy (anonymous):
okay thank you!!
OpenStudy (gorv):
@coolkat4
t^2=x-1
t^2=y+1
implies x-1=y+1
y=x-2
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