Mathematics
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OpenStudy (anonymous):
How to find a?
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OpenStudy (anonymous):
OpenStudy (anonymous):
what trig function does this represent?
OpenStudy (anonymous):
a^2 = b^2 + c^2 - 2(a)(b) - cos A?
OpenStudy (gorv):
sin39=a/15
OpenStudy (anonymous):
what function would you use when you are trying to find the adjacent side and you have the hypotenuse?
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OpenStudy (anonymous):
cosine?
OpenStudy (anonymous):
soh cah toa. so yes cosine :) so you would do cos 39=a/15, multiply by 15 to get a by itself. so you are left with
15 sin 39
OpenStudy (anonymous):
why did it change to sin?
OpenStudy (anonymous):
it was never sin.
OpenStudy (anonymous):
crap sorry i didnt mean sin D: 15 cos 39!
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OpenStudy (anonymous):
and am I right on this one?
OpenStudy (anonymous):
yes you are :D
OpenStudy (anonymous):
and what would this one be?
OpenStudy (anonymous):
it would just be cos 5/13, it cant be reduced.
OpenStudy (anonymous):
no it can't. & what about this one? Am I right
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OpenStudy (anonymous):
Am I right on this one too?
OpenStudy (anonymous):
@Hope_nicole
OpenStudy (anonymous):
tangent is opp/adj. so it would be 36/15
OpenStudy (anonymous):
alright so Im right on this one?
OpenStudy (anonymous):
other way around.
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OpenStudy (anonymous):
why you said oop/adj?
OpenStudy (anonymous):
Am I doing it right now? :o
OpenStudy (anonymous):
yeah that one is right
OpenStudy (anonymous):
Alright & I have no idea what this is asking for?
OpenStudy (anonymous):
do you know what csc is?
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OpenStudy (anonymous):
nope
OpenStudy (anonymous):
yes its cotanget?
OpenStudy (anonymous):
csc is the inverse of sin...so its 1/sin..
OpenStudy (anonymous):
so it would be:
OpenStudy (anonymous):
no cotangent is cot, the inverse of tangent.
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OpenStudy (anonymous):
alright so this is the inverse of sin?
OpenStudy (anonymous):
well sin is 12/15/ so you need the inverse of that.
OpenStudy (anonymous):
so 5/4
OpenStudy (anonymous):
so this one is false its 13/5
OpenStudy (anonymous):
& so secant is the reciprical of sine?
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OpenStudy (anonymous):
secant is the inverse of cosine
OpenStudy (anonymous):
Alright so On this one am I right?
OpenStudy (anonymous):
@Hope_nicole
OpenStudy (anonymous):
yeah :D
OpenStudy (anonymous):
so this one is false right?
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OpenStudy (anonymous):
They forgot to flip it? @Hope_nicole
OpenStudy (anonymous):
correct so its false
OpenStudy (anonymous):
THANKS SOOO SOOO SOOOO SOOO MUCH! @Hope_nicole
OpenStudy (anonymous):
anytime :D