Question

If I do a self cross between a heterozygous AaLlRr what's the probability...

Answer 1

Of getting an all homozygous dominant? Homozygous recessive?

Answer 2

Answer says \(\frac{ 1 }{8}\) for homozygous Dom, but why isn't it also the same for recessive?

Answer 3

there will be 8 different gamete genotypes
ALR
ALr
Alr
aLR
alR
AlR
aLr
alr

8x8 = 64 different offspring genotypes
If you draw a punnett square for this one and you'll see that only 1 offspring will have a homozygous genotype for all alleles. And only 1 has a recessive genotype for all alleles.

change of all homozygous dominant is 1 out of 64. same for full recessive.
added the square so you can see it.

Answer 4

It answer showed 1:8 for three homozygous dominant, but 1:64 for homozygous recessive. Which is where I was lost thanks for the clarification