You are to construct an open rectangular box with a square base and a volume of 48 ft^3. If material for the bottom costs $6/ft^2 and the material for the sides costs $4/ft^2 what dimensions will result in the least expensive box. What are its dimensions.

Question

You are to construct an open rectangular box with a square base and a volume of 48 ft^3.  If material for the bottom costs $6/ft^2 and the material for the sides costs $4/ft^2 what dimensions will result in the least expensive box.  What are its dimensions.

anonymous · Answer

so I get we are minimizing$$48=x^2h$$

anonymous · Answer

and $$h=\frac{ 48 }{ x^2 }$$

anonymous · Answer

so what is the function i need to calculate to get the dimensions?  or what do i do next?