Question

Solve. 10/(3x) + 4/3 = (7 + x)/2x
A) x = 1/3
B) x = 17/5x
C) x = 1/5
D) x = 1/6

help??

Answer 1

well first expand the right side

Answer 2

10/(3x) + 4/3 = (7 + x)/2x

multiply through by x

10/3 +4x/3 =(7+x)/2

multiply through by 6 to get rid of the denominators

10*2 + (4x)(2) = (7+x)(3)

expand and solve for x. it should be doable now.

Answer 3

@tomo it isn't, I'm sorry I'm just so bad at math! :-( can you help me through this entire equation so I can try the next by myself?

Answer 4

10*2 + (4x)(2) = (7+x)(3)

20 + 8x = 21 + 3x

8x-3x = 21-20

5x = 1

x = ?

Answer 5

@tomo so it's A??

Answer 6

please write down what you are doing, because otherwise i can't tell what you are struggling with or thinking.

Answer 7

@tomo I'm just so confused.. please, can you just show me how you do the entire problem

Answer 8

10/(3x) + 4/3 = (7 + x)/2x

multiply through by 6x to get rid of the denominators. (this is the least common denominator)

so

6x[10/(3x)] +(6x)(4/3) = (6x)[(7+x)/(2x)]

2*10 + 2x*(4) = 3*(7+x)

20 +8x = 21 + 3x

subtract 20 from each side

8x = 21-20 +3x

8x = 1 + 3x

subtract 3x from both sides

8x-3x = 1

5x = 1

x = 1/5