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Mathematics 8 Online
OpenStudy (anonymous):

cosx(1+tan^2x)

OpenStudy (anonymous):

\[1+\tan ^{2}x=\sec ^{2}x\]

OpenStudy (anonymous):

that's an identity, then you're left with cos and sec^2 from there you can simplify it again

OpenStudy (anonymous):

how do you do simplify it again?

OpenStudy (anonymous):

secx=1/cos, right?

OpenStudy (anonymous):

i think

OpenStudy (anonymous):

cosx(1+tan^2x) cosxsecx cosx/cosx 1

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