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Mathematics 10 Online
OpenStudy (anonymous):

verify sinx+cosxcotx=cscx

OpenStudy (anonymous):

can you write cotx in terms of sine and cosine? cotx = ???

OpenStudy (anonymous):

1/tanx

OpenStudy (anonymous):

... in terms of sine and cosine...

OpenStudy (anonymous):

oh cosx/sinx

OpenStudy (anonymous):

ok... good... so...

OpenStudy (anonymous):

\(\large sinx+cosxcotx \) = \(\large sinx+cosx \frac{cosx}{sinx} \) = \(\large sinx+\frac{cos^2x}{sinx} \) now, in order to add these two, they must have the same denominator... what is it?

OpenStudy (anonymous):

= \(\large sinx+\frac{cos^2x}{sinx} \) = \(\large \frac{sinx}{1}+\frac{cos^2x}{sinx} \) they must have the common denominator of sinx.... agreed?

OpenStudy (anonymous):

o sorry yeah

OpenStudy (anonymous):

so... = \(\large \frac{sinx}{1}+\frac{cos^2x}{sinx} \) = \(\large \frac{sinx}{sinx} \cdot \frac{sinx}{1}+\frac{cos^2x}{sinx} \) = \(\large \frac{sin^2x}{sinx}+\frac{cos^2x}{sinx} \) = \(\large \frac{sin^2x + cos^2x}{sinx} \) = i think you can take it from here?

OpenStudy (anonymous):

yes thank you

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