Write the standard equation for the circle that passes through the points (1, 1), (1, 3), and (9, 2). So I know d=-79 but I dont' know e or f
General equation is\[x^2 + y^2 + dx + ey + f = 0\] first equation is \[-2 = d + e + f\] Second equation is\[-10 = d + 3e + f\] third equation is \[-85 = 9d + 2e +f\]
First minus second gave me e=-4 second minus third gave me \[75 = -8d + e\] e=-4 minus the other gave me \[d=-79/8\]
But x & y are multiplied by 8 so then d would then be -79. But what would that make e? -4/8 = -1/2. But I tried that answer and it did not work
I know that in order to find f I need to find d & e, which I know the answer to d (-79) but not e
Its cool that your using equations to solve for it (like a boss), but just graph the points. From there, you can easily figure out the radius and center. Once you have that, plug it into the equation (x-h)^2 + (y-k)^2 = r^2 Where h is the x component of the center, k is the y component and r^2 is the radius squared. From there, factor everything out and you have your answer
Haha thanks. But I just called my teacher (I'm homeschooled) to see if I could use that way on a test. He said no.. So I have to figure out how to do it his way.. Haha which wouldn't be so bad until you get to the super tricky ones.
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