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Algebra 24 Online
OpenStudy (anonymous):

I need help factoring a couple of problems!!!

OpenStudy (anonymous):

post

OpenStudy (anonymous):

x2 – 8x + 15

OpenStudy (anonymous):

Its (x-5)(x-3) but i dont know what to do after

OpenStudy (mathstudent55):

Her's how you factor a trinomial: 1. Try to factor a common factor out of all terms if possible. In your example, there is no common factor.

OpenStudy (anonymous):

thats is these are the required factors

OpenStudy (anonymous):

*it

OpenStudy (mathstudent55):

2. If the trinomial is of the form x^2 + ax + b, then dollow the next steps. In your case, you do have a trinomial of the form x^2 + ax + b, since the coefficient of the x^2 term is 1.

OpenStudy (mathstudent55):

3. Look for two numbers that multiply to b and add to a. In your case look for two numbers that add to 15 and add to -8

OpenStudy (mathstudent55):

4. The numbers are -3 and -5 Write (x )(x ) and fill in the balnks with the numbers, so you get (x - 3)(x - 5)

OpenStudy (anonymous):

Yea i got that so after i fill in the blanks i just put the whole problem together and solve?

OpenStudy (mathstudent55):

You asked for help in factoring. The facoring is done. x^2 - 8x + 15 = (x - 3)(x - 5) If your problem was simply a factoring problem, you are done. If your problem was to solve the equation, x^2 - 8x + 15 = 0, then after factoring you need to continue until you get a solution for x. In that case this is what you do: x^2 - 8x + 15 = 0 (x - 3)(x - 5) = 0 x - 3 = 0 or x - 5 = 0 x = 3 or x = 5

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