Question

Solve using substitution.

6x^2+3y^2=12
y=-x+2

Answer 1

plug the second equation, where it is solve for y already....into the first equation.

Answer 2

6x^2+3(-x+2)^2 = 12 -------------->like this

Answer 3

solve for x first, then after you get the x plug the number you got for x into either equation and that will help you get the y value.

Answer 4

This is what I've done so far
6x^2+3(-x+2)^2=12
6x^2+3(x^2-4x+4)=12
6x^2+3x^2-12x+12=12
9x^2-12x=0

Answer 5

x(9x-12)=0
Now try solving

Answer 6

x=0, 4/3?

Answer 7

You got it =)

Answer 8

Now plug those values in to get the values for y

Answer 9

Okie dokes! Thank you!

Answer 10

Yup no problem :)