Which graph models the equation -3x + 2y = 6? What number does it fall on the x axis and y axis
first solve for y, do you know how to do that?
no
do i add 3 to both sides
-3x + 2y = 6 yes +3x +3x 2y = 3x + 6 now what?
what is keeping the y from being alone?
uhmmm. it has 2 in front of it
right....it is 2times y , do the opposite to get rid of it
divide both sides by 2
3x + 3
but on a graph on my x axis will my line cross three and cross the y axis to enter my 2nd quadrant
-3x + 2y = 6 yes +3x +3x 2y = 3x + 6 now what? -- -- -- 2 2 2 y = 3/2x + 3
when you divide both sides by 2, you have to divide everything by the 2
y = mx + b y = 3/2x + 3
oh ok so when i divide 3 by 2 whats the next time after that
6/ 2 = 3 y = mx + b y = 3/2x + 3 what is the y intercept?
2x i think
NO 3
so itll be 2 on the x axis and cross and fall on the 3 on the y axis if im correct
yes 3 is the y intercept, that is where the line crosses the y axis set y = to 0 and solve for x to see where it crosses the x axis -3x + 2y = 6 -3x + 2(0) = 6 solve for x
ok when i multiply and my 2 is gone do i add 3x to both sides or.. 6 im assuming 3 but then i get um 3=6
and now i guess if it is 3=6 i um divide 3 by both sides which leads to the conclusion of 3/6 = 2 right ?
divide both sides by -3 6/-3 = -2
the line crosses the x axis at -2
thanks jim can you help me with with other problem
A geometric sequence is defined by the recursive formula t1 = 64, tn = tn - 1 2 , where n ∈N and n > 1. The sequence is
t1 = 64, tn = tn -2 , is that right?
i have to find the next 6 terms starting with 64
A) 64, 16, 8, 4, 2, 1, ... Eliminate B) 64, 32, 16, 8, 4, 2, ... C) 64, 128, 256, 512, 1024, 2048, ... D) 128, 256, 512, 1024, 2048, 4096, ... these are the choices
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