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Calculate the scalar projection and projection of (5,3) onto (7,-2)
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|dw:1366808943725:dw| cant recall the def of a "scalar projection" to clearly tho
essentially you take the unit of v (the onto vector) and multiply it by the |u| cos(a), where a is the angle between them
Ok, so how would you calculate it through the coordinates they gave me?
\[cos(\alpha)=\frac{u\cdot v}{|u|~|v|}\] \[|u|~cos(\alpha)=\cancel{|u|}\frac{u\cdot v}{\cancel{|u|}~|v|}=|proj_uV|\]
u = (5,3) ; length of u v = (7,-2) ; length of v --------- dot them we will need to find these properties in order to plug them into the formula
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hmmm, from the google i get that |u| cos(a) is defined as the SCALAR projection, the magnitude of proj_u V
|dw:1366809318162:dw|
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