Question

use the quadratic formula to find any x-intercepts on the graph of the equation.
y=5x^2+6x-6

Answer 1

Found it.

Answer 2

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 3

Thank you!!!!!!!!!

Answer 4

That is the quadratic formula. In your problem a =5, b = 6, c = -6
Plug in those values and solve.

Answer 5

i wish I post what I got so far but I dont have the format

Answer 6

Use the equation button below this box

Answer 7

DUH!!!

Answer 8

\[\frac{ -6\pm \sqrt{45} }{ 10 }\]

Answer 9

\[x=\frac{-6\pm \sqrt{6^2-4(5)(-6)}}{2(5)}=\frac{-6\pm \sqrt{36+120}}{10}\]

Answer 10

how?!

Answer 11

Negative times negative = positive

Answer 12

oooooh!! I messed up

Answer 13

\[\frac{ -6\pm \sqrt{156} }{ 10 }\]