a group consisting of 25 teachers, 20 engineers, 18 doctors and 12 salesmen visited a fair and spent Rs 1330 altogether.It was found that 5 teachers spent as much as 4 engineers, 12 engineers spent as much as 9 doctors and 6 doctors spent as much as 8 salesmen.if every person in a professional gruop spent the same amount, find the amount spent by each engineer
you can set a set of equations to solve that problem. to make clear, I set T (teacher) , E (engineer), D(docor)and S (salesmen) set x is the hours 1 teacher spent. --> 25x is the amount of hours group Teacher spent set y is the hours/ 1 Doctor spent--> 18y is the amount of hours/ group Doctor spent set z is hours/ 1 Engineer spent ---> 20z is total amount of hours of group Engineer set t is hours /1 Salesman spent ---> 12 t is total amount of hours of group Salesmen Now, set up equation: 8t =6y 9y =12z 4z = 5x and 25x +18y+20z+12t = 1330 you have 4 equations, and 4 variables. You can solve it to find out the answer by using either substitute or make a matrix method. hope I understand the problem on the way it is. If it's not that. Sorry friend. I am useless
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