Factor completely: 10x^2 + 2x − 8

A) 2(5x − 1)(x + 4)

B) 2(5x − 4)(x + 1)

C) 2(5x + 2)(x − 2)

D) 2(5x − 2)(x + 2)

Question

Factor completely: 10x^2 + 2x − 8

A) 2(5x − 1)(x + 4)

B) 2(5x − 4)(x + 1)

C) 2(5x + 2)(x − 2)

D) 2(5x − 2)(x + 2)

anonymous · Answer

@Notamathgenius

anonymous · Answer

2(x+1)(5x-4)

goformit100 · Answer

its easy, do you know the basics of quadratic Expression.

cwrw238 · Answer

first divide by 2 

= 2(5x^2 + x - 4)

anonymous · Answer

Then what?

goformit100 · Answer

Dont just kee on giving answering directly

anonymous · Answer

@Nurali

cwrw238 · Answer

then you need to factor the quadratic  5x^2 + x - 2 

have you done these in class yet?

anonymous · Answer

no its a 5 question pretest. Im not allowed to look ahead and get the gist of anything until I do my pretest.

cwrw238 · Answer

well you can try expanding each of the options util you get  the original expression

can you you work out (5x - 2)(x + 1)  using the distributive law ?

anonymous · Answer

I dont know.

anonymous · Answer

the answers is B

cwrw238 · Answer

well you multiply the second bracket by 5x then by - 2:

= 5x(x + 1) - 2(x + 1)

can you do that?

cwrw238 · Answer

can you continue from there?

cwrw238 · Answer

@julianchico  -  its best not to just give the answer - but to explain how to get the answer - otherwise there is little benefit to the questioner.