Question

Simplify:
8x^2 - x^3/16 - 2x

Answer 1

\[\frac{ 8x ^{2}-x ^{3} }{ 16-2x}\]

Answer 2

7x^2 / 2(8-x)

Answer 3

Can you show me the work? @Annetta_Martin

Answer 4

Can you factor x^2 out of the numerator?

Answer 5

Yeah , right? @Mertsj

Answer 6

Did you do it?

Answer 7

I'm not good at factoring. @Mertsj

Answer 8

How would you factor it out entirely? @Mertsj

Answer 9

\[\frac{ 8x^2-x^2 }{ 16-2x }\]
\[\ 8x^2-x^2 = 7x^2\]
16-2x = 2(8-x) because 2*8=16 and 2*x = 2x

so: \[\frac{ 8x^2-x^2 }{ 16-2x }=\frac{ 7x^2 }{ x(8-x) }\]

Answer 10

Thank you! But the equation is 8x2-x^3 not x squared. @thomaster

Answer 11

F