Question

Can anyone please help me with my Calculus questions? I will appreciate your help!!

Answer 1

whats the question...?

Answer 2

oh thanks there is someone who can help me :)

Answer 3

perhaps... depends on the question

Answer 4

we are looking for f(x) when f '(x) is giving

Answer 5

f ' (x) = (x+3)(2x-5)

Answer 6

ok... so its integral calculus...

distribute f'(x)

so you have

f'(x) = 2x^2 + x - 15

now it should be easier to find the indefinite integral.

Answer 7

if you dont mind can you help me out doing this question bcoz my teacher didnt explain it well.

Answer 8

ok... the the basics of integration is

\[\int\limits x^n dx = \frac{1}{n + 1}x^{n + 1} + c\]

you need to apply this rule to each term

so start with

\[2x^2\]

add 1 to the power.. and write 1 over the new power.

Answer 9

ok

Answer 10

here is the 1st term

\[\int\limits2x dx = 2 \times \frac{1}{3}x^3 = \frac{2}{3}x^3\]

Answer 11

oh ok

Answer 12

oops should have read

\[\int\limits 2x^2 dx = 2 \times \frac{1}{3} x^3 ..= \frac{2}{3}x^3\]

Answer 13

ok

Answer 14

so thats 2 times where is 2x

Answer 15

well its 2 times 1/(x+1) x^(n +1)

Answer 16

ok

Answer 17

so what will be our next step?

Answer 18

well you need

\[\int\limits x.. dx \]

what do you think that will be..?

Answer 19

hmmm I m really not getting this :(

Answer 20

do what would you differentiate to get

x..?

Answer 21

x^3?

Answer 22

I m stuck can you correct me ?

Answer 23

not quite

if you differentiated and get x, it means you started with

\[\frac{x^2}{2}\]