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use method of cylindrical shells to find volume of solid obtained by rotating region bounded by curves about specified axis: y= e^x, y=e^-x, x=1 about the y axis
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Use \(2\pi rh dr\) as your model. \(2\pi\int\limits_{0}^{1}x\left(e^{x}-e^{-x}\right)\;dx\) Verify with washers, using \(\pi r^{2}dh\) as your model \(\pi\int\limits_{1/e}^{1}1^{2} - (-ln(y))^{2}\;dy + \pi\int\limits_{1}^{e}1^{2} - (ln(y))^{2}\;dy\) Sorry, these are just too compelling. Make sure you see where ALL of that comes from.
i got the setup right but i must not be integrating right. i used integration by parts
i'm getting 2pi (2e+ 2e^-1 -2)
Nevermind I got it! Thank you!
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