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Mathematics 8 Online
OpenStudy (anonymous):

...

hartnn (hartnn):

hi :) do you know the formula for n'th term of arithmetic series ?

OpenStudy (anonymous):

Nope hehe

hartnn (hartnn):

hehe, so here it is! \(\large a_n=a_1+(n-1)d\) where a1 is the 1st term and d is the common difference :)

OpenStudy (anonymous):

Thanks! :D

OpenStudy (anonymous):

But wait, how can I get the firt term then? :))

hartnn (hartnn):

yo get 5th term , you put n=5!

OpenStudy (anonymous):

can you show the step by step solution? :) :D

hartnn (hartnn):

ok, lets start. for 5th term , n=5 so, from that formula \(\large a_5 = a_1+4d\) got this ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you have 8th and 15th terms put n=8 and n =15 you will get two equations solve them for 8th term n=8 9= a1+7d 30=a1+14d

hartnn (hartnn):

oh, wait, why did you need 5th term ?

OpenStudy (anonymous):

I mean the first term

OpenStudy (anonymous):

Because you have two unknowns... the first term and the common difference ^_^

OpenStudy (anonymous):

Oh wait...

hartnn (hartnn):

lol, ok...the first term is a1, which you need to find. from 15th and 8th term

OpenStudy (anonymous):

Yes...

hartnn (hartnn):

so, lets start with 8th term 8th term , n=8 so, from that formula a8=a1+7d got this ?

OpenStudy (anonymous):

yes

hartnn (hartnn):

15th term , n=15 so, from that formula a15=a1+14d got this ?

OpenStudy (anonymous):

where did 14 came? hehe

hartnn (hartnn):

an = a1 + "(n-1)" d n was 15 , so n-1 = 14

OpenStudy (anonymous):

okok :)

OpenStudy (anonymous):

Hey, @hartnn if it helps, maybe you can have this instead.. \[\large a_n = a_m +(n-m)d\] you can find d immediately

hartnn (hartnn):

we can use that, but since this is just start of the topic, lets keep it simple and standard.

OpenStudy (anonymous):

I guess

hartnn (hartnn):

so, we have a15=a1+14d = 30 and a8=a1+7d = 9 can you think of a way to find a1 from here ? @gcgmpng ?

hartnn (hartnn):

hint : multiply 2nd equation by 2 (or -2)

OpenStudy (anonymous):

what to do after multiplying?

hartnn (hartnn):

did you multiply ? what you got ? then you subtract (or add) the 2 equations.

OpenStudy (anonymous):

2a8=a1+7d=18?

hartnn (hartnn):

a8 ?? the 2 equations were a1+14d = 30 and a1+7d = 9

hartnn (hartnn):

after multiplying by 2, in the 2nd equation, you get 2a1 +14 d = 18 right ?

OpenStudy (anonymous):

yes

hartnn (hartnn):

now subtract a1+14d = 30 from 2a1 +14 d = 18 what you get ?

OpenStudy (anonymous):

12

hartnn (hartnn):

correct! a1 = 12 good :) thats your 1st term. any doubts ?

OpenStudy (anonymous):

None :D THANK YOU! \:D/

hartnn (hartnn):

welcome ^_^

hartnn (hartnn):

oh, wait!

hartnn (hartnn):

isn't it a1 = -12 ??

OpenStudy (anonymous):

Yes, yes it is!Haha

hartnn (hartnn):

ok.....glad we corrected that immediately...

OpenStudy (anonymous):

Thank you again! :D

hartnn (hartnn):

then welcome again!

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