Question

is it correct?

4x^2-y^2+2y-1 = 4x^2-(y-1)^2
=(2x-y-1)(2x+y-1)

16p^2-(5q-r)^2 = 16p^2=(4p)(4p)
5q-r^2=(5q-r)(5q+r)
=(4p+5q-r)(4p-5q+r)

Answer 1

almost

Answer 2

4x^2-y^2+2y-1
= 4x^2-(y-1)^2
= ( 2x - (y-1) ) ( 2x + (y-1) ) = ( 2x - y + 1 ) ( 2x + y - 1)

Answer 3

the other one is correct?

Answer 4

\[16p^2-(5q-r)^2 = (4p - (5q-r)) (4p + (5q-r)) = ( 4p - 5q + r) (4p +5q -r) \]

Answer 5

im sorry you did it right :D

Answer 6

thank you perl im just making sure, im not confident with my answer and sometimes i forget how to do it. specially in factoring and groupings.

Answer 7

this is not right however
5q-r^2=(5q-r)(5q+r) !!! false

Answer 8

ok then ill try to rewrite it.

Answer 9

oh i see the problem

Answer 10

it said ( 5q - r)^2 , not 5q-r^2 , which is different

Answer 11

\[16p^2-(5q-r)^2 \\= (4p - (5q-r)) (4p + (5q-r)) \\= ( 4p - 5q + r) (4p +5q -r)\]

Answer 12

thank you perl i got it, but im confused to this 2y^2-3z = what supposed to be the answer?

Answer 13

you should just leave it be :)

Answer 14

\[2y^2-3z \]

Answer 15

cant it be (y+3z)(y-3z)?