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OpenStudy (anonymous):
I have sin 2x = sin2(75) cos(75)
OpenStudy (anonymous):
i don't know how to edit
OpenStudy (anonymous):
i have sin 150 but i don't know what to do with cos75
OpenStudy (anonymous):
hey, sin 2x = 2sinx cos x
OpenStudy (anonymous):
what did i do wrong?
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OpenStudy (anonymous):
2(75) cos(75)
OpenStudy (anonymous):
you miss 2 before sin x cos x
OpenStudy (anonymous):
ok, Madina, You wrong at the beginning , You have the form already , you have 2 sin 75 cos 75 = sin 2*75= sin 150 . look up the value of sin 150 plug there and you got the answer
OpenStudy (anonymous):
\[-\sqrt{3}/2\]
OpenStudy (anonymous):
cannot be that, 150 at quadrant 2, sin in that region cannot be negative
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OpenStudy (anonymous):
yes cos is negative there
OpenStudy (anonymous):
but yours is end up at sin
OpenStudy (anonymous):
what do you mean?
OpenStudy (anonymous):
you calculate for sin 150 , it cannot be - sqr .....
OpenStudy (anonymous):
i honestly don't see what i am missing
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OpenStudy (anonymous):
you don't have to do anything, why you calculate cos 75?