Question

Show work and explain steps! Medal will be received if answer is correct! :D

Answer 1

\[\frac{ 6a - 1 }{ 2a + 7 } + \frac{ 22 }{ a + 5 } = 3\]

Answer 2

what is the use of the medals? i cant get money from that

Answer 3

you'll get a medal is what I am saying

Answer 4

so what u need to do there?
solve for a?

Answer 5

I just need help getting there

Answer 6

First, you need to have a common denominator.
\[\frac{ 6a - 1 (a+5) }{ (2a + 7)(a+5) }+\frac{ 22(2a+7) }{ (2a + 7)(a+5) } =\frac{ 3 (2a + 7)(a+5) }{(2a + 7)(a+5) }\]

Since you have the same denominators for all of them, when you add and then cross multiply, they will cancel out. We can just work on the numerators.

FOILED: \[(6a-1)(a+5) = 6a ^{2}+29a-5\]
Distributed: \[22(2a+7) = 44a+154\]
FOIL the parentheses first:
\[3(2a+7)(a+5) = 2a ^{2}+17a+35\]
You should have this after you foiled:
\[3\times2a^{2}+17a+35\]
Now distribute the 3:
\[3\times2a^{2}+17a+35= 6a ^{2}+51a+38\]
You should have:
\[(6a ^{2}+29a-5) + (44a+154) = 6a ^{2}+51a+38\]

Answer 7

3 x 35 is NOT 38

Answer 8

How would you solve this @Mertsj

Answer 9

*114 OOPS.

Answer 10

I would multiply every term by the common denominator thus cancelling all denominators.

Answer 11

Did you read that I said it would cancel all denominators?

Answer 12

yes

Answer 13

so what would it be

Answer 14

Why don't you do it and find out. ilikechicken had it almost done for you except that little error where she added instead of multiplied.

Answer 15

Did you do it?

Answer 16

I am trying to figure it out: How did she get 6a^2 + 29a - 5???

Answer 17

Multiplied (6a-1)(a+5)