@jim_thompson5910 help me please
Write an equation that could be used to find the m
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OpenStudy (anonymous):
OpenStudy (anonymous):
@goformit100
jimthompson5910 (jim_thompson5910):
Given this triangle
|dw:1366941696728:dw|
we can use the law of cosines to say
c^2 = a^2 + b^2 - 2ab*cos(C)
or
b^2 = a^2 + c^2 - 2ac*cos(B)
or
a^2 = b^2 + c^2 - 2bc*cos(A)
OpenStudy (anonymous):
idk what to do
OpenStudy (anonymous):
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
which side is opposite angle R
OpenStudy (anonymous):
ummm 72
jimthompson5910 (jim_thompson5910):
72? how are you getting that
OpenStudy (anonymous):
i have no idea
OpenStudy (anonymous):
idk help maybe?
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jimthompson5910 (jim_thompson5910):
|dw:1366942216203:dw|
jimthompson5910 (jim_thompson5910):
circle the side that's opposite angle R
OpenStudy (anonymous):
oh 5!
jimthompson5910 (jim_thompson5910):
no that side is part of angle R
OpenStudy (anonymous):
6?
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jimthompson5910 (jim_thompson5910):
angle S is opposite the side that's 6 units long
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
i still dont get it lol
jimthompson5910 (jim_thompson5910):
the opposite side is basically the side that's furthest from the angle
OpenStudy (anonymous):
so its 7
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OpenStudy (anonymous):
jim you there boo?
jimthompson5910 (jim_thompson5910):
yes the side length that's 7 units is opposite angle R
OpenStudy (anonymous):
ok what do i do now
jimthompson5910 (jim_thompson5910):
so you'll have something of the form
7^2 = a^2 + b^2 - ab*cos(R)
where you'll replace a and b with the proper values
OpenStudy (anonymous):
52 ad 62?
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jimthompson5910 (jim_thompson5910):
5^2 and 6^2, yes
OpenStudy (anonymous):
ok now what
jimthompson5910 (jim_thompson5910):
a = 5 and b = 6, you just said it
jimthompson5910 (jim_thompson5910):
so plug them in
OpenStudy (anonymous):
is this A B C or D
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