Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (boobear7411):
OpenStudy (boobear7411):
Yes
OpenStudy (boobear7411):
Why ?
OpenStudy (boobear7411):
Multiply
OpenStudy (boobear7411):
@Mertsj helppp meee
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (boobear7411):
@amistre64 hellllpppmeeee
OpenStudy (amistre64):
your best bet is to factor that left denominator, i think theres a x-2 hiding in it
OpenStudy (boobear7411):
i have no idea how to do this.
OpenStudy (amistre64):
you have to be able to factor that one denominator
OpenStudy (amistre64):
factoring the top part would simplify it as well
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (boobear7411):
but i dont know how to
OpenStudy (amistre64):
then you should go back and read up on those sections ..... you are clearly not prepared to work the problem
OpenStudy (boobear7411):
Okey dokey
OpenStudy (amistre64):
if you could give me something to work with other than " i cant, i dont know" and such that would be useful. otherwise this would take way to long to try to teach you on here
OpenStudy (boobear7411):
Alright umm on the first one whats my first step ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
look at the x^2 - 1, this is a setup that would be familiar of you could recall a difference of squares
OpenStudy (boobear7411):
ok. .
OpenStudy (amistre64):
the bottom of it, might factor into (x-2)(x+n)
so foiling it should give us something to compare with
OpenStudy (boobear7411):
Like this ??
OpenStudy (amistre64):
like that yes :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (boobear7411):
so umm you take (x-2)(x+n) and foil it ?
OpenStudy (amistre64):
i would, that would be the simplest way to compare what they have so that we can determine a value of "n"