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2/5+1/5t=1/5 solve.
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Use parenthesis please :)
t=-1
2/5-1/5=1/5
\[\frac{ 2 }{ 5 }+\frac{ 1 }{ 5t }=\frac{ 1 }{ 5 }\] \[\frac{ 10t+5 }{ 25t }=\frac{ 1 }{ 5 }\] \[10t+5=5t\] \[5t=-5\] \[t==-1\]
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so what if it was 2/5+1/2t=1/5
\[\frac{ 2 }{ 5 }+\frac{ 1 }{ 2t }=\frac{ 1 }{ 5 }\] \[\frac{ 4t +5}{ 10t }=\frac{ 1 }{ 5 }\] \[4t+5=2t\] \[2t=-5\] \[t=\frac{ -5 }{ 2 }\]
thanks nurali :)
My pleasure.
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yes there will be ill let you know when i need help :)
ok
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