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what is the derivative of 3x^2/3?
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The derivative of equations of the form \[f(x)=c*x^{n}\] where c is a constont are equal to \[f'(x)=c*nx^{n-1}\] Try that on your equation
so i would do 3*2/3*x^2/3-1?
Yes
ok so 2x^1/3
Close. 2/3 - 1 = -1/3
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if i want to solve for x. and the equation is 2x^-1/3=0 how do i get rid of the -1/3
You don't really need to. Because x=0 will give you a zero no matter what power x is raised to
You could raise both powers to the 1/3 power \[(2x^{-1/3})^{1/3} = 0^{1/3}\] \[(2x^{-1/3})^{-3} = 0^{-3}\] \[2x = 0\]
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