Question

How Do I solve for x

3 = -2x^2+x+3

Answer 1

What two numbers when multiplied give you -6, but when added give you 1?

Answer 2

-3 and 2

Answer 3

Oh wait, i see there's a three. Subtract 3 from both sides and set it equal to zero. Then factor out an "x".

Answer 4

yea i have 0 = 2x^2+x

Answer 5

Factor out an "x".

Answer 6

0= -x(2x-x)

Answer 7

Not quite. When you factor out an "x" from the second term you shouldn't have an 'x there.

Answer 8

yea sry it sould be 1

Answer 9

Ok, now you have x = 0 and (2x-1) = 0
solve for "x" in the second equation by using ur algebra tools.

Answer 10

(2x-1)=0
2x = 1
x=1/2

Answer 11

Am I right?

Answer 12

Yep. So your values for x = \(\frac{1}{2}\) and 0

Answer 13

But how is the second value 0, that I do not understnad

Answer 14

x(2x-1) = 0
^
I
I
because you're setting these equal to zero. Hence x = 0 and x = (2x-1)