Question

Help Please!
http://prntscr.com/12c7k3

Answer 1

@.Sam.

Answer 2

i chose C

Answer 3

\[2|x+\frac{1}{3}|<9\]
Square both sides,
\[4(x+\frac{1}{3})^2<81 \\ \\ (x+\frac{1}{3})^2<\frac{81}{4} \\ \\ x^2+\frac{2 x}{3}+\frac{1}{9}< \frac{81}{4}\]

Answer 4

\[x^2+\frac{2x}{3}-\frac{725}{36}<0 \\ \\(6x-25)(6x+29)<0 \\ \\ x=\frac{25}{6}~,~x=-\frac{29}{6}\]

\[\large-\frac{29}{6}<x<\frac{25}{6}\]
Understand?

Answer 5

just to mention an alternative method :
|a+b| > c
---> a+b > c or a+b < -c
solve these 2 equations separately to get 2 inequalities

Answer 6

so A

Answer 7

@.Sam.

Answer 8

yes. A

Answer 9

Use the vertical-line test to determine which graph represents a function

Answer 10

http://prntscr.com/12c9vr

Answer 11

there are three graphs which is the correct one

Answer 12

I think its the third one

Answer 13

ok, imagine a vertical line,
move that vertical line from left to right of the graph., if you find 2 or more points of intersection , then the graph is not a function.
and its not 3rd.

Answer 14

so B

Answer 15

yes.

Answer 16

http://prntscr.com/12cakw

Answer 17

according to the graph its C

Answer 18

it must be |x-5 |
- means shift right
then
|...| +5
+ means shift up

Answer 19

so... ?

Answer 20

wouldn't it be D then ?

Answer 21

-5+5

Answer 22

hmm ?
y <= |x-5| +5

Answer 23

SO D

Answer 24

yes.

Answer 25

http://prntscr.com/12ccfe

Answer 26

Its b

Answer 27

@.Sam.