Question

Simplify

12x^3 - 8x^2y - 16x/4x =

Answer 1

\[12x^3-8x^2y-\frac{ 16x }{ 4x }\]
\[12x^3-8x^2y-\frac{ 16x*x }{ 4 }\]
\[12x^3-8x^2y-\frac{ 4x^2 }{ 1 }\]
\[12x^3-8x^2y-4x^2\]

Answer 2

love u

Answer 3

i think it should be simplified more

Answer 4

It don't see how it can be simplified further

Answer 5

3x4+6x3+x2
3x2-2xy-4
3x2+2x+1
None of the above

Answer 6

oh you can divide it by 4 so you'll get \[3x^3-2x^2y-x^2\]So i guess it's none of the above

Answer 7

it is wrong

Answer 8

\[4x ^{3} - 2x ^{2}y - 1\]

Answer 9

that is correct

Answer 10

theomaster, the second step is wrong. You can't do that, its dividing not multiplying

Answer 11

I see :P something went wrong there.
16x/4x=4

But the answer would still be none of the above

Answer 12

yes